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4x^2+330x+397=0
a = 4; b = 330; c = +397;
Δ = b2-4ac
Δ = 3302-4·4·397
Δ = 102548
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{102548}=\sqrt{4*25637}=\sqrt{4}*\sqrt{25637}=2\sqrt{25637}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(330)-2\sqrt{25637}}{2*4}=\frac{-330-2\sqrt{25637}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(330)+2\sqrt{25637}}{2*4}=\frac{-330+2\sqrt{25637}}{8} $
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